Question

if tan A =3/2 then what is the value of cos A​

Answer 1

In triangle ABC

Bc=3 and AB=2

Using pythagoras theorem

AC^2 =AB^2+BC^2

=2^2+3^3

= 4+9

AC^2=13

AC=Saquare root of 13

There fore

Cos A=2÷root 3

Answer 2

The value of Cos A is $\frac{2}{3.6}$

Step-by-step explanation:

$Tan \theta = \frac{Perpendicular}{Base}$

We are given that $Tan A = \frac{3}{2}$

On comparing

Perpendicular = 3

Base = 2

To find hypotenuse

$Hypotenuse^2 = Perpendicular^2+Base^2\\Hypotenuse^2=3^2+2^2\\Hypotenuse=\sqrt{3^2+2^2}\\Hypotenuse=3.6$

$Cos \theta = \frac{Base}{Hypotensue}\\Cos A = \frac{2}{3.6}$

Hence The value of Cos A is $\frac{2}{3.6}$

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