Question

if tan theta + 1 upon 10 theta is equal to 2 find the value of 10 squared theta + 1 upon 10 square theta​

Answer 1

Step-by-step explanation:

tanO + 1/tanO = 2

square Karne per

(tanO + 1/tanO)² = 4

tan²O + 1/tan²O + 2 = 4

tan²O + 1/tan²O = 2

Answer 2

We need to recall the following property of the square of a sum.

• $(a+b)^{2} = a^2+b^2+2ab$

Given:

$tan(\theta)+\frac{1}{tan(\theta)} =2$

Take a square of both sides.

$(tan(\theta)+\frac{1}{tan(\theta)})^2 =2^2$

$tan^2(\theta)+\frac{1}{tan^2(\theta)}+2tan(\theta)\frac{1}{tan(\theta)} =4$

$tan^2(\theta)+\frac{1}{tan^2(\theta)}+2 =4$

$tan^2(\theta)+\frac{1}{tan^2(\theta)} =4-2$

$tan^2(\theta)+\frac{1}{tan^2(\theta)} =2$