if tan theta/2=2-root of 3 then sin theta =?
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tan∅/2 = 2-√3
use formula,
sin∅ = 2tan∅/2/(1+tan²∅/2)
=2(2-√3)/(1+7-4√3)
=2(2-√3)/(8-4√3)
=2(2-√3)/4(2-√3)
=1/2
use formula,
sin∅ = 2tan∅/2/(1+tan²∅/2)
=2(2-√3)/(1+7-4√3)
=2(2-√3)/(8-4√3)
=2(2-√3)/4(2-√3)
=1/2
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