Question

if tan theta =√3,then find the value of 2sec theta by 1+tansquare theta​

Answer 1

$tan \theta = \sqrt{3} \\ \\ \theta = 60 \degree \\ \\ now \: \: \: \: \: \: \frac{2sec \theta}{1 + {tan}^{2} \theta } \\ \\ = \frac{2sec60 \degree}{1 + {tan}^{2} 60\degree } \\ \\ = \frac{2 \times 2}{1 + ( { \sqrt{3} })^{2} } \\ \\ = \frac{4}{4} \\ \\ = 1$