Question

If tan theta =4/3,show that (sin theta + cos theta) =7/5

Answer 1

tan theta = p/b = 4 /3

hence sin theta = p/h so in a right angle triangle p=4 and b = 3

so we get h= 5 by Pythagoras theorem

so we get sin theta = 4/5

cos theta = b/h = 3/5

so sin theta + cos theta = 4/5+3/5

which equals to 7/5 proved

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Answer 2

tan theta=4(P)/3(B)

by pythagoras theorem

H^2=P^2+B^2

H^2=4^2+3^2

H^2=16+9 =25

H^2=25

H=5

sin theta + cos theta

sin theta =P/H=4/5

cos theta=B/H=3/5

4/5+3/5

=7/5

hence proved