If tan theta is 12/5 then value of sin theta is
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Answered by
18
Hi ,
Here I am using A instead of theta.
tanA = 12/5
CotA = 5/12
Cosec² A = 1 + cot² A
= 1 + ( 5/12 )²
= 1 + 25/144
= ( 144 + 25 ) / 144
= 169 / 144
cosecA = √ ( 13/12 )²
1/sinA = 13/12
Therefore ,
SinA = 12/13
I hope this helps you.
: )
Here I am using A instead of theta.
tanA = 12/5
CotA = 5/12
Cosec² A = 1 + cot² A
= 1 + ( 5/12 )²
= 1 + 25/144
= ( 144 + 25 ) / 144
= 169 / 144
cosecA = √ ( 13/12 )²
1/sinA = 13/12
Therefore ,
SinA = 12/13
I hope this helps you.
: )
Answered by
8
Hey there! ☺☻☺
Given,
Tan θ = 12/5
Then Cot θ = 5/12
We know,
Cosec² θ = 1 + cot² θ
= 1(5/12)²
= 1+ 25/144
= 169/144
= (13/12)²
Then, Cosec θ = √(13/12)²
So, 1/Sinθ = 13/12
∴ Sin θ = 12/13 [reciprocal]
Hope It Helps You! ☺☻☺
Given,
Tan θ = 12/5
Then Cot θ = 5/12
We know,
Cosec² θ = 1 + cot² θ
= 1(5/12)²
= 1+ 25/144
= 169/144
= (13/12)²
Then, Cosec θ = √(13/12)²
So, 1/Sinθ = 13/12
∴ Sin θ = 12/13 [reciprocal]
Hope It Helps You! ☺☻☺
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