If tan theta + sec theta is equal to 2/ 3 then sec theta is
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tan∅ +sec∅ = 2/3
tan∅=sin∅/cos∅
sec∅ = 1/cos∅
sin∅/cos∅ + 1/cos∅ = 2/3
(sin∅ + 1)/cos∅ = 2/3
sin∅=1-cos²∅
(1-cos²∅+1)/cos∅ = 2/3
(-cos²∅)/cos∅ = 2/3
-cos∅ = 2/3
cos∅ = -2/3
1/cos∅ = sec∅ = -3/2
sec∅ = -3/2
If tan theta + sec theta is equal to 2/ 3 then sec theta is -3/2
tan∅=sin∅/cos∅
sec∅ = 1/cos∅
sin∅/cos∅ + 1/cos∅ = 2/3
(sin∅ + 1)/cos∅ = 2/3
sin∅=1-cos²∅
(1-cos²∅+1)/cos∅ = 2/3
(-cos²∅)/cos∅ = 2/3
-cos∅ = 2/3
cos∅ = -2/3
1/cos∅ = sec∅ = -3/2
sec∅ = -3/2
If tan theta + sec theta is equal to 2/ 3 then sec theta is -3/2
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Answer:
Step-by-step explanation:
tan∅ +sec∅ = 2/3
tan∅=sin∅/cos∅
sec∅ = 1/cos∅
sin∅/cos∅ + 1/cos∅ = 2/3
(sin∅ + 1)/cos∅ = 2/3
sin∅=1-cos²∅
(1-cos²∅+1)/cos∅ = 2/3
(-cos²∅)/cos∅ = 2/3
-cos∅ = 2/3
cos∅ = -2/3
1/cos∅ = sec∅ = -3/2
sec∅ = -3/2
If tan theta + sec theta is equal to 2/ 3 then sec theta is -3/2
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