If tan theta + sec theta is equal to L then prove that sec theta is equal to L square + 1 by 2L
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I = tanФ + secФ
I - secФ = tanФ
l² + sec²Ф - 2 l secФ = tan²Ф
= sec²Ф - 1
So secФ = (l² + 1) / 2l
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