Question

if tan2 A= cot(A-18°),where 2A is an acute angle, find the value of A
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Answer 1

Answer:

ANSWER

Given tan2A=cot(A−18

0

)

⇒cot(90−2A)=cot(A−18

0

)[∵tanθ=cot(90−θ)]

Comparing angles we get

90−2A=A−18

⇒90+18=A+2A

⇒3A=108

⇒A=

3

108

⇒A=36

∘

Answer 2

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