Question

if tan2A=cot(A-18) where 2A is an acute angle. find the value of A

Answer 1

Heya !! ☺

tan2A = cot(A-18)
cot(90-2A) = cot(A-18)
90-2A = A-18
90+18 = 2A+A
3A = 108
A = 108/3
=> 36

Hope my ans. is satisfactory.

Answer 2

tan2A=cot90-(A-18)

tan2A=tan108-A
on removing tan from both side we will get:
2A=108-A
3A=108
A=108/3
A=36
(^_^)