If tan2A=cot(A-18°),where 2Ais an acute angle,find the value of A.
Answers
Answered by
3
Answer:
tan 2A = cot ( A - 18 )
cot (90 - 2A ) = cot (A - 18 )
90 - 2A = A - 18
90 - 18 = 3A
3A = 72
A = 24 °
hope it helps
Answered by
46
Answer:
Hey mate answer of your question is given below by me...
Step-by-step explanation:
Given that..
tan 2A=cot(A-18 degree)
tan 2A= cot (90degree-2a)
cot(90-2a)= cot(A-18)
90 degree -2A and A-28 degree both are acute angle ..
Therefore...
90-2A=A-18.
-2A-A=-18-90
-3A= -108
A= -108/-3
A= 36 degree
Your answer is 36 degree..
I hope it can help you...
Similar questions