Question

SIMPLIFY LOG 0.6BAR TO THE BASE 1.5

Answer 1

Answer:

Your answer is.......

Use below log rules

Log (1÷a)= Log (a^-1)

Log a^b=b Log a

Now, log0.1= log(1/10) =log (10^-1) =-1 log10.......

Here log 10= 1 . (From table)

So -1 log10= -1(1)= -1. Ans.

Next, log 0.5 = log (1/2) = log (2^-1) = -1 log 2

Here log 2 = ( From table)

So, -1 log 2= -1(0.30103)

= -0.30103 Ans

Hope it helps......☺️☺️☺️

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Answer 2

Answer:

Use below log rules

Log (1÷a)= Log (a^-1)

Log a^b=b Log a

Now, log0.1= log(1/10) =log (10^-1) =-1 log10.......

Here log 10= 1 . (From table)

So -1 log10= -1(1)= -1. Ans.

Next, log 0.5 = log (1/2) = log (2^-1) = -1 log 2

Here log 2 = ( From table)

So, -1 log 2= -1(0.30103)

= -0.30103 Ans

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