Question

if tanA = -4/3, 3r/2<A<2r find the value of 3 secA + tanA

Answer 1

check this image ...I hope this is correct.

Answer 2

since tanA = sinA/cosA
sinA=-4/5 and cosA= 3/5
since root over( (-4)^2+3^2)= 5

secA=5/3, tanA= -4/3

so 3secA+tanA=3*5/3-4/3=11/3