Question

if tanA=9/40,then secA is​

Answer 1

Answer:

Given: tan A= 9/40

To find : secA

Solution:

TanA = 9/40

We know that ,

1+tan²A= sec²A......... ( Trigonometric identity)

1+ ( 9/40)²= sec²A

1+ 81/ 1600= sec²A

1681/1600= sec²A

i.e sec²A = 1681/1600

secA= 41/40 ....... ( By taking +ve square roots)