Question

If tanA+secA=m and tanA-secA=n then prove that m²-n²= 4√mn

Answer 1

Answer:

SteOct 29, 2018 — Here given is, TanA +sinA = m, TanA- sinA = n, Now LHS, m² - n² (tanA + sinA)² - (​tanA - sinA)² ... How do I prove 1+secA-tanA/1+secA+tanA = 1-sinA/cosA? ... If tanA+sinA=a & 4√ab=a^2-b^2, then what is the proof that tanA-sinA=b? ... If tanA​+SinA=m and tanA-sinA=n then we prove that m^2 - n^2 =4√(mn) as follows.p-by-step explanation:

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