Question

if tangent PA and pb from a point p to a circle with centre o are inclined at a angle of 80 then poa is equal to​

Answer 1

Answer:

50 degrees

Step-by-step explanation:

BPA and BOA are supplementary.

so BOA is 100 degrees.

wen line PO divides the quadrilateral it separates it into two equal halves.

by RHS congruency the 2 triangles are congruent and by CPCT , POA = POB

POA + POB = 100 degrees

2POA = 100 degrees

POA = 50 degrees

Answer 2

Answer:

APB= 80

OA=OB........(1)

AP=BP..........(2)

OP common ......(3)

by sss congruency ,

                             triangle AOP congruent to BOP

                                and angle APO=BPO

therefore angle APO =40

AOP+APO+OAP=180

AOP+40+90 =180

           AOP=180-130

            AOP=50

therefore angle POA=50

Step-by-step explanation: