Question

If tanQ+secQ=5/2,then find sec Q

Answer 1

Answer:

Tan q =

$\sqrt{ {sec}^{2} q \: - 1}$

Root (Sec^2 q - 1) = (5/2 - sec Q) ^ 2

On squaring bith side

Sec^2 Q - 1 = 25/4 + sec^2Q - 5sec Q

Sec^2 get cut out of the equation

5sec Q = 25/4 + 1

Sec Q = 29/4*5

Sec Q = 29/20