If , prove that fof is identity function.
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any function is said to be identity function that always returns the same value that was used as its argument. mathematically, identity function is written as f(x) = x.
now, f(x) = (2x + 3)/(3x - 2)
fof = f(f(x)) = f[(2x + 3)/(3x - 2)]
= {2(2x + 3)/(3x - 2) + 3}/{3(2x + 3)/(3x - 2) - 2}
= {2(2x + 3) + 3(3x - 2)}/{3(2x + 3) -2(3x - 2)}
= {4x + 6 + 9x - 6}/{6x + 9 - 6x + 4}
= 13x/13
= x
hence, fof = x
it is clear that, fof is an identity function.
now, f(x) = (2x + 3)/(3x - 2)
fof = f(f(x)) = f[(2x + 3)/(3x - 2)]
= {2(2x + 3)/(3x - 2) + 3}/{3(2x + 3)/(3x - 2) - 2}
= {2(2x + 3) + 3(3x - 2)}/{3(2x + 3) -2(3x - 2)}
= {4x + 6 + 9x - 6}/{6x + 9 - 6x + 4}
= 13x/13
= x
hence, fof = x
it is clear that, fof is an identity function.
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