Question

If
$\frac{1}{a + 1} + \frac{1}{b + 1} + \frac{1}{c + 1} = 2$
then what is the value of
${a}^{2} + {b}^{2} + {c}^{2}$
?

Answer 1

put a=0
b=1
and c=1
now,
a^2+b^2+c^2=0^2+1^2+1^2
=2