Math, asked by deep3337, 1 year ago

If
 \frac{1}{a + 1}  +  \frac{1}{b + 1}  +  \frac{1}{c + 1}  = 2
then what is the value of
 {a}^{2}  +  {b}^{2}  +  {c}^{2}
?

Answers

Answered by gauravansuman
1
put a=0
b=1
and c=1
now,
a^2+b^2+c^2=0^2+1^2+1^2
=2

deep3337: Thank you
gauravansuman: wlcm
deep3337: But can you tell me another process ?
gauravansuman: ok I will try to solve and send u
deep3337: ok
gauravansuman: u can write this equation like that 1/a+1 + 1/b+1 +1/c+1 = 0+0+2 or 0+1+1
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