Question

If
${x}^{4} + \frac{1}{ {x}^{4} } = 7$
Then, find the value of
${x}^{2} + \frac{1}{ {x}^{2} }$
​

Answer 1

Step-by-step explanation:

x⁴+1/x⁴=7

Add both sides 2,we get

x⁴+1/x⁴+2=7+2

x⁴+1/x⁴+2(x⁴*1/x⁴)=9

${( {x}^{2} + \frac{1}{ {x}^{2} }) }^{2} = 9$

${x}^{2} + \frac{1}{ {x}^{2} } = 3$