Question

if
$x = a (\cos(theta) + \sin(theta) )$
and
$y = a( \sin(theta) - \cos(theta) )$

then prove that
$\frac{ {d}^{2}y }{ d {x}^{2} } = \frac{ { \sec(theta) }^{3} }{a \: theta}$
​

Answer 1

Explanation:

$\frac{ {d}^{2}y }{ d {x}^{2} } = \frac{ { \sec(theta) }^{3} }{a \: theta}$