Math, asked by tal46, 1 year ago

if
$x + \frac{1}{x} = 3$
Then find the value of
${x}^{2} + \frac{1}{ {x}^{2} }$

Answers

Answered by prernaraj

$x + \frac{1}{x} \: = 3 \\ on \: squaring \: both \: side \\ we \: get... \\ {(x + \frac{1}{x} )}^{2} = {3}^{2} \\ = > {x}^{2} + \frac{1}{ {x}^{2} } + 2 \times \frac{1}{x} \times x = 9 \\ = > {x}^{2} + \frac{1}{ {x}^{2} } = 7 \: answer$

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Answered by parvd

Answer:

Step-by-step explanation:

x+ 1/x=3

square both sides.

it will be :-

x²+1/x²=9-2

x²+1/x²=7

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if
$x + \frac{1}{x} = 3$
Then find the value of
${x}^{2} + \frac{1}{ {x}^{2} }$