if
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Answered by
16
Hello friend,
Here's your answer:
Answer = -218
In the pic, it went wrong a bit.
Sorry for that
Explantation = Refer the pic
Hope my answer helps you.
Here's your answer:
Answer = -218
In the pic, it went wrong a bit.
Sorry for that
Explantation = Refer the pic
Hope my answer helps you.
Attachments:
Bunti360:
answer is -218 bro, You have to do (-2)³ not (-2)², Edit it !.. by the way great way of solving !.. :) !.
Answered by
6
Here is the solution :
1st Equation : x-y = 2,
2nd Equation : xy = 35,
Simplifying 1st Eq,
=> y = x+2 --------- 3rd Equation,
Substituting 3rd Eq in 2nd Eq,
=> (x)(x+2) = 35,
=> x² + 2x = 35,
=> x² + 2x - 35 = 0,
=> x² + 7x - 5x - 35 = 0,
=> x(x+7) -5(x+7) = 0,
=> x-5 = 0, or x+7 = 0,
=> x = 5, or x = -7, Substituting these values in 1st Eq,
=> If x = 5 :
y = 5+2 = 7,
=> If x = -7,
y = -7+2 = -5,
=> x³ - y³ = either 5³ - 7³ or -7³ - (-5)³
=> x³ - y³ is always -218,
Therefore : x³ - y³ = -218
There is also another way to find !. But in this way, we can have x and y values too !..
Hope you understand, Have a Great day !..
Thanking you, Bunti 360 !..
1st Equation : x-y = 2,
2nd Equation : xy = 35,
Simplifying 1st Eq,
=> y = x+2 --------- 3rd Equation,
Substituting 3rd Eq in 2nd Eq,
=> (x)(x+2) = 35,
=> x² + 2x = 35,
=> x² + 2x - 35 = 0,
=> x² + 7x - 5x - 35 = 0,
=> x(x+7) -5(x+7) = 0,
=> x-5 = 0, or x+7 = 0,
=> x = 5, or x = -7, Substituting these values in 1st Eq,
=> If x = 5 :
y = 5+2 = 7,
=> If x = -7,
y = -7+2 = -5,
=> x³ - y³ = either 5³ - 7³ or -7³ - (-5)³
=> x³ - y³ is always -218,
Therefore : x³ - y³ = -218
There is also another way to find !. But in this way, we can have x and y values too !..
Hope you understand, Have a Great day !..
Thanking you, Bunti 360 !..
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