Question

If the 39th and 51st terms of an AP are 59 and 31 Respectively..
Then which term of this AP is equal to 0​

Answer 1

Step-by-step explanation:

a39= 59

a51= 31

a39=a+38d

59=a+38d {1}

a51=a+50d

31=a+50d {2}

from 1 and 2 equation

59=a+38d

31=a+50d

- - -

28= -12d

28/-12=d

-2=d

Put the value of d in 2nd equation

31=a+50d

31=a+50(-2)

31=a+(-100)

31=a-100

31+100=a

131=a

given that

an=0

an=a+(n-1)d

0=131+(n-1)-2

-131=-2n+2

-133=-2n

n= -133/-2

In this Ap any one term is not 0

Answer 2

Answer:

I don't know the answer