If the 3rd and the 9th term of an ap are 4 and -8 respectively, which term of it is zero?
Answers
therefore a+2d = 4→1
9th term of A.P = -8
therefore a+8d = -8→2
On subtracting 2 from 1
a+2d = 4
-(a+8d = -8)
⇒a+2d = 4
-a - 8d = 8
⇒ -6d = 12
d = -2
On substituting the value of d in a+2d = 4 we get a = 8
let 0 be the last term of the A.P
therefore a+(n-1)d = 0
⇒ 8 + (n-1)-2 = 0
8-2n+2 = 0
⇒-2n = -10
n = 5
therefore 5th term of the A.P is 0
☺ Hello mate__ ❤
◾◾here is your answer...
It is given that 3rd and ninth term of AP are 4 and -8 respectively.
It means ᵃ₃=4 and a₉=−8 where, a₃ and a9 are third and ninth terms respectively.
Using formula an=a+(n−1)d, to find nth term of arithmetic progression, we get
4 = a + (3-1)d And, -8 = a + (9-1)d
⇒4=a+2d And, −8=a+8d
These are equations in two variables. Lets solve them using method of substitution.
Using equation
4=a+2d,
we can say that
a=4−2d.
Putting value of a in other equation
−8=a+8d,
we get
−8=4−2d+8d
⇒−12=6d
⇒d=−126=−2
Putting value of d in equation
−8=a+8d,
we get
−8=a+8(−2)
⇒−8=a−16
⇒a=8
Therefore, first term =a=8 and
Common Difference =d=−2
We want to know which term is equal to zero.
Using formula an=a+(n−1)d, to find nth term of arithmetic progression, we get
0=8+(n−1)(−2)
⇒0=8−2n+2
⇒0=10−2n
⇒2n=10
⇒n=102=5
Therefore, 5th term is equal to 0.
I hope, this will help you.
Thank you______❤
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