Question

If the 4th 10th and 16th term of a gp are x y and z respectively prove that x y z are in gp

Answer 1

Answer:

4 , 10 ,16 Is defined okkkkk

Answer 2

Step-by-step explanation:

ar^3=x

ar^9=y

ar^15=z

xz=a^2r^18

ar^9=y--------

(ar^9)^2=y^2 (Squaring on both sides)

y^2=a^2r^18

ie, y^2=xz

y=√xz ----(GM)

Hence x, y, z are in GP

Hope it helps...