If the 4th
term of A.p is - 15 and 9th term is -30 find the 23th A.P
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GIVEN :
4th term of A.p is = - 15
9th term = -30
TO FIND :
the 23th term of the A.P
FORMULA USED :
Tn ( nth term) = a+ (n-1)d
SOLUTION :
Tn ( nth term) = a+ (n-1)d
4th term = a+ (4-1)d = a+ 3d
-15 = a+ 3d
a= -15-3d ........ (1)
9th term = a+ (9-1)d = a+ 8d
-30 = a+ 8d
-30-8d = a.........(2)
equating (1) and (2) ,
-15-3d. = -30-8d
-15+30= 3d -8d
15= -5d
-3= d
a= -15-3d
a= -15 + 9
a= -6
23rd term = a+(23-1)d
= -6+ (22×-3)
= -6 + (-66)
= - 72
ANSWER : -72
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