if the 8th term of an AP is zero prove that it's term 38th is triple of
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Step-by-step explanation:
ANSWER
T
8
=a+7d=0
⇒a=−7d
T
38
=a+37d
=−7d+37d
=30d
T
18
=a+17d
=−7d+17d
=10d.
Clearly T
38
=3(T
18
).
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