If the absolute temperature of a gas having volume v cm3 is doubled nd the pressure is reduced to half ,what will be the final volume ?
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PV/T = P'V'/T' (combined gas law)
P - initial pressure
V - initial volume
T - initial temperature
P' - final pressure = P/2
V' - final volume
T' - final temperature = 2T
PV/T = (P/2)V'/2T
V' = 4V cm^3
so, final volume will be 4V
P - initial pressure
V - initial volume
T - initial temperature
P' - final pressure = P/2
V' - final volume
T' - final temperature = 2T
PV/T = (P/2)V'/2T
V' = 4V cm^3
so, final volume will be 4V
jackhenry:
Thnks, but it is just like bouncer for me
p1v1/t1 = p2v2/t2 this is combined gas law
i know that. Ket me solve myself
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