Question

if the angles of a triangle are x minus 40 degree x minus 20 degree and 1 by 2 x minus 10 degree find the angles

Answer 1

i hope you understand

Answer 2

according to the question

x-40-1st angle;;x-20-2nd angle;;1/2x-10-3rd angle

Using angle sum property of triangles

x-40+x-20+1/2x-10=180

x+x+1/2x=180+40+20+10(getting all the variables on one side )

2x+1/2x=250(solving the equations)

4x+1x=250×2(adding 2x and1/2x and cross multiplication)

5x=250×2

x=250×2/5

x=100

angles=

1st-x-40=100-40=60

2nd-x-20=100-20=80

3rd-1/2x-10=1/2×100-10=50-10=40