Question

If the angular diameter of the Jupiter is 36" and its distance from the earth is 8.25 ×10^8
km then find the diameter of the Jupiter.
​

Answer 1

Answer:

Distance of jupiter from the earth (D)=825×10

6

×10

3

m=8.25×10

11

Angular diameter (θ)=36

′

=36×4.874×10

−6

rad=1.75×10

−4

As we know that,

θ=

D

d

⇒d=θ×D

⇒d=1.75×10

−4

×8.25×10

11

=1.44×10

8

m=1.44×10

5

km

Hence the diameter of the jupiter is 1.44×10

5

km.