If the area of triangle abc with vertices [x,3] [4,4] and [3,5] is 4 sq units find x
Answers
Answered by
9
Answer:
x=-3
Step-by-step explanation:
Area of triangle having vertices
Given:
Area of the triangle = 4 Sq.units
x(4-5)+4(5-3)+3(3-4)= 8
-x+8-3=8
x=-3
x=-3
Step-by-step explanation:
Area of triangle having vertices
Given:
Area of the triangle = 4 Sq.units
x(4-5)+4(5-3)+3(3-4)= 8
-x+8-3=8
x=-3
Answered by
5
given,
area of triangle = 4 sq unit .
vertices of triangle are : (x, 3), (4, 4) and (3, 5)
we know,
if (x1, y1) , (x2, y2) and (x3, y3) are vertices of triangle then, area of triangle = 1/2 [x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)]
so, area of given triangle = 1/2 [x(4 - 5) + 4(5 - 3) + 3(3 - 4)]
or, 4 = 1/2 [-x + 4 × 2 + 3 × -1 ]
or, 8 = -x + 8 - 3
or, - x - 3 = 0
or, x = -3
hence, value of x = -3
area of triangle = 4 sq unit .
vertices of triangle are : (x, 3), (4, 4) and (3, 5)
we know,
if (x1, y1) , (x2, y2) and (x3, y3) are vertices of triangle then, area of triangle = 1/2 [x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)]
so, area of given triangle = 1/2 [x(4 - 5) + 4(5 - 3) + 3(3 - 4)]
or, 4 = 1/2 [-x + 4 × 2 + 3 × -1 ]
or, 8 = -x + 8 - 3
or, - x - 3 = 0
or, x = -3
hence, value of x = -3
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