If the area of triangle whose vertices are p( -2 ,0 ) , Q ( 3,0) , R ( 0 , k ) is 9 unit then find the value of k
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Answer:
We know that , area of a triangle with vertices (a
1
,y
1
),(x
2
,y
2
) and (x
3
,y
3
) is given by
Δ=
2
1
∣
∣
∣
∣
∣
∣
∣
∣
x
1
x
2
x
3
y
1
y
2
y
3
1
1
1
∣
∣
∣
∣
∣
∣
∣
∣
∴Δ=
2
1
∣
∣
∣
∣
∣
∣
∣
∣
−3
3
0
0
0
k
1
1
1
∣
∣
∣
∣
∣
∣
∣
∣
Expanding along R
1
9=
2
1
[−3(−k)−0+1(3k)]
⇒18=3k+3k=6k
∴K=
6
18
=3
Step-by-step explanation:
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