If the average of 5 consecutive numbers is 27 find the smallest number
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let the consecutive numbers be x,x+1,x+2,x+3,x+4.
then. x+x+1+x+2+x+3+x+4/5
=5x+10/5
=5(x+2)/5
=x+2
it is given average is27 then
x+2=27
x=27-2
x=25
th smallest number is x then it is 25
then. x+x+1+x+2+x+3+x+4/5
=5x+10/5
=5(x+2)/5
=x+2
it is given average is27 then
x+2=27
x=27-2
x=25
th smallest number is x then it is 25
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