If the charge of an electron is 1.6 x 10-19 coulomb, how many electrons should pass through a conductor in 1 second to constitute 1 ampere of current
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Answered by
9
I=ne/t
1=n x 1.6 x10^-19/1
0.625×10^19=n
n=6.25×10^18 electrons
1=n x 1.6 x10^-19/1
0.625×10^19=n
n=6.25×10^18 electrons
Answered by
3
Answer:
6.25 X 10^18
Explanation
I = ne/t
so here 1.6 X 10^-19 is the charge of the electron
so . n X 1.6 X 10^-19/ 1
1 = n X 1.6 X 10^-19/1
bringing n to one side
n = 0.625 X 10^-19
n = 6.25 X 10^18
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