if the coordinates of one end of a diameter of a circle are 2, 3 the coordinates of it centres are 2 - 25 then find the coordinates of the other end of the diameter
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Let coordinate of one point diameter be
A(2,3) and center be O(2,-25)
and other end of diameter be B(x,y)
By using distance formula
d(A,O)=√(x2-x1)²+(y2-y1)²
=√(2-2)²+(-25-3)²
=√0+(-28)²
=√(28)²
=28
The diameter AB is double of radius and AO is the radius
Thus,
AB=2×AO
=2×28
=56
A(2,3) and center be O(2,-25)
and other end of diameter be B(x,y)
By using distance formula
d(A,O)=√(x2-x1)²+(y2-y1)²
=√(2-2)²+(-25-3)²
=√0+(-28)²
=√(28)²
=28
The diameter AB is double of radius and AO is the radius
Thus,
AB=2×AO
=2×28
=56
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