Question

If the coordinates of the mid point of the sides of a triangle are (1,1),(2,-3) and (3,4).then find the centroid?

Answer 1

Answer:

Step-by-step explanation:

Hope this will help you...

Answer 2

Answer:

$Centroid(G)= \big(2,\frac{2}{3}\big)$

Step-by-step explanation:

$The\: coordinates \: of \\</p><p>the \: mid\:point \:of \: the \: sides \\of\:a\:triangle\:are\\</p><p>(1,1),(2,-3)\:and\:(3,4)$

$x_{1}=1,y_{1}=1;\\x_{2}=2,y_{2}=-3;\\x_{3}=3,y_{3}=4$

$Now,\\Centroid (G)=\big(\frac{x_{1}+x_{2}+x_{3}}{3},\frac{y_{1}+y_{2}+y_{3}}{3}\big)$

$=\big(\frac{1+2+3}{3},\frac{1-3+4}{3}\big)\\=\big(\frac{6}{3},\frac{2}{3}\big)\\=\big(2,\frac{2}{3}\big)$

Therefore,

$Centroid(G)= \big(2,\frac{2}{3}\big)$

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