Question

If the cube of a natural number ends with a prime digit then the probability of it's fourth power not ending with a prime digit is

Answer 1

Answer:

1 ✔..................

Answer 2

Answer:

Probability = 0

Step-by-step explanation:

We know for numbers ending in:

1 => 1³ = 1  and 1⁴ = 1

2 => 2³ = 8  and 1⁴ = 16

3 => 3³ = 27  and 3⁴ = 81

4 => 4³ = 64  and 4⁴ = 256

5 => 5³ = 125  and 5⁴ = 625

6 => 6³ =  216 and 6⁴ = 1296

7 => 7³ =  343 and 7⁴ = 2401

8 => 8³ = 512  and 8⁴ = 4096

9 => 9³ = 729  and 9⁴ = 6461

0 => 0³ = 0  and 0⁴ = 0

Numbers whose cubes ends with a prime number = 1, 3, 5, 7

Numbers whose cubes ends with a prime number  but the fourth power does not = None

We know probability = $\frac{Number of favourable outcomes}{Total number of outcomes}$

Here, total number of outcomes = 4

Favorable outcomes = 0

Therefore, probability = 0