if the daigonal of a rombus is 12cm and 16 cm then the area of the rombus is
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Answer:
Formula : 1/2*d1*d2
Step-by-step explanation:
d1 = 12 cm
d2 = 16 cm
Area of the rhombus: 1/2*12*16
= 96
Area of rhombus: 96 cm square
Answered by
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Step-by-step explanation:
ac=16
bd=12
ao=8
bo=6
angle aob=90°
in right angle triagle angle aob
( by paythagoriean triplet)
ab^2=ao^2+ ob^2
ab^2=8^2+6^2
ab^2= 100
ab=10
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