If the diagonals of a parallelogram are equal, then show that it is a rectangle
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Step-by-step explanation:
- The opposite angles of a parallelogram are equal.
- The opposite sides of a parallelogram are equal.
- The diagonals of a parallelogram bisect each other
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Figure:-
Given:-
- The diagonals of a parallelogram are equal.
Solutions:-
- Let ABCD be a parallelogram.
To Show:-
- Let ABCD be a rectangle.
Prove that:-
- One of its interior angle.
In ∆ABC and ∆DCB,
AB = DC (Opposite sides of a parallelogram are equal)
BC = BC (Common)
AC = DB (Given)
.:. ∆ABC ~ ∆DCB (By SSS Congruence rule)
<ABC ~ <DCB
The sum of the measures of angle on the same side of transversal is 180°
<ABC + <DCB = 180° (AB//CD)
<ABC + <ABC = 180°
2<ABC = 180°
<ABC = 180°/2
<ABC = 90°
Hence, ABCD is a parallelogram and one of its interior angle is 90°, ABCD is a rectangle.
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