if the diagonals of a rhombus are 12 centimetre and 16 cm find the length of each side
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d1=12cm
d2=16cm
1/2d1=6cm
1/2d2=8cm
side^2=1/2d1^2+1/2d2^2 [Refer the attachment][By Pythagoras theorem]
side^2=6^2+8^2
side=√36+64
side=√100
side=10 cm
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d2=16cm
1/2d1=6cm
1/2d2=8cm
side^2=1/2d1^2+1/2d2^2 [Refer the attachment][By Pythagoras theorem]
side^2=6^2+8^2
side=√36+64
side=√100
side=10 cm
HOPE THIS HELPS YOU BUDDY ✌
IF YOU LIKE IT PLEASE MARK IT AS BRAINLIEST!!!!
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