Physics, asked by chetancpatil3826, 7 months ago

If the diameter of the wire is halved it's current carrying Will become about

Answers

Answered by coco50

Answer:

Explanation:

If the diameter is halved, the area becomes 1/8th times the initial area, therefore the currents carrying capacity increases 8 times the initial current carrying capacity.

R(resistance)= [(resistivity of conductor) * (length of wire)] / (area of cross section)

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