if the differnece between two number is 8 and the difference between the squares is 160 then what are the numbres
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1
let the number be x and y
x-y=8. eq1
x²-y²=160
(x+y)(x-y)=160
(x+y)8=160
x+y=20 eq2
adding eq1 and eq2
2x=28
x=14
y=6
I hope so it will be useful
please mark it as brainliest
x-y=8. eq1
x²-y²=160
(x+y)(x-y)=160
(x+y)8=160
x+y=20 eq2
adding eq1 and eq2
2x=28
x=14
y=6
I hope so it will be useful
please mark it as brainliest
Answered by
0
Answer:
Step-by-step explanation:
Let us suppose the number be x ana y.
Then,
According to 1st case
x-y=8.............1
According to 2nd case
x^-y^=160............2
Consider equation no. 1
x-y=8
x=y+8......3
Putting value of x in equation no. 2
(y+8)^-y^=160
y^+64+16y-y^=160
16y=160-64
16y=96
y=96/16
y=6
Putting value of y in equation no. 1
x-y=8
x-6=8
x=8+6
x=14
So the no.be 14 and 6
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