If the discriminant of equation 6x2-bx+2=0 is 1,Find the value of b
Answers
Answered by
124
(b^2-4*6*2)^1/2 =1
Squareing both sides
=> b^2-4*6*2=1
=>b^2-48=1
=>b^2=48+1
=>b^2=49
=>b=+/-(49)^1/2
=>b=+/-7
Hence
b=7 or b=-7
Squareing both sides
=> b^2-4*6*2=1
=>b^2-48=1
=>b^2=48+1
=>b^2=49
=>b=+/-(49)^1/2
=>b=+/-7
Hence
b=7 or b=-7
Answered by
79
Answer:
Value of b = ±7
Explanation:
Given quadratic equation :
6x²-bx+2=0
Compare this equation with
Ax²+Bx+C = 0 , we get
A = 6, B = -b , C = 2
Discreminant (D) = 1[Given]
=>B²-4AC = 1
=> (-b)²-4×6×2=1
=> b²-48=1
=> b² = 1+48
=> b² = 49
=> b = ±√49
=> b = ±7
Therefore,
Value of b = ±7
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