Question

if the displacement of a particle varies with time according to the relation x=K/b[1-exp(-bt)],then the velocity (v) of the particle is
a)v=K exp(-bt)
b)v=K/b exp(-bt)
c)v=K² exp(-bt)
d)v=K/b² exp(-bt)

Answer 1

if the displacement of a particle varies with time according to the relation $\bf{x=\frac{K}{b}[1-e^{-bt}]}$

differentiate x with respect to t,
$\frac{dx}{dt}=\frac{K}{b}\{\frac{d1}{dt}-\frac{d(e^{-bt})}{dt}\}$

$v=\frac{K}{b}[0-(-b)e^{-bt}]$
$v=\frac{K}{b}\times be^{-bt}$
$v=Ke^{-bt}$

hence, option (a) is correct

Answer 2

Answer:

option a  is correct

Explanation:

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