Question

If the distance between two plates of a parallel plate capacitor is doubled its capacity

Answer 1

The capacitance between plates will reduce to half of the original value.

•Capacitance is defined as the ratio between "change in an electric charge in a system to the corresponding change in its electric potential."

•C = Q/V

•Capacitance between capacitor plates is given by the formula C = epsilon*area/distance

•Epsilon is the absolute permissivity of the dielectric material

•A is the area of parallel plate

•D is the distance between capacitor plates

•So, when distance is doubled

•C = epsilon*area/2*distance

•Thus, capacitance will be half of the original value.

Answer 2

Explanation:

• When we consider different types of capacitors parallel plate capacitor is the most commonly addressed among them.
• We have also studied about its dependency on different aspects like permittivity distance and area.  
• When one of the factors has a change in them, there will be a certain change in the value of capacitance for the capacitor.

Capacitance between parallel plates is, C = $\frac{\epsilon \times A}{d}$

Where,

$\epsilon$ is the absolute permissivity of dielectric material.

A is the area of the parallel plate.

d is the distance between the parallel plates.

• It will see the effect, hence when the doubling of distance is discussed. Then the capacitance will be,

                                                C = $\frac{\epsilon \times A}{2d}$

The capacitance will be doubled.

To know more:

When you charge given to a capacitor is doubled its capacitance

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