if the distance of p(x,y) from A(5,1) and B(-1,5) are equal then prove that 3x=2y
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PA=PB
(5_x)^2+(y_1)^2=1_x)^2+(5_y)^2
25+x^2+x^2_10x+y^2+1_2y=1+x^2_2x+25+y^2_10y
=18x=12y
=3x=2y
(5_x)^2+(y_1)^2=1_x)^2+(5_y)^2
25+x^2+x^2_10x+y^2+1_2y=1+x^2_2x+25+y^2_10y
=18x=12y
=3x=2y
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