Math, asked by fayyaztolhr, 1 month ago

if the domain of the function f:x= 2x^2 +1 is {-1,2,3} the range of the function is ___?​

Answers

Answered by ansazafarullah
1

Step-by-step explanation:

Correct option is

B

Doman=R,Range=(−∞,2]

Given f(x)=2−∣x−5∣

Domain of f(x) is defined for all real values of x.

Since, ∣x−5∣≥0⟹−∣x−5∣≤0

⟹2−∣x−5∣≤2⟹f(x)≤2

Hence, range of f(x) is (−∞,2].

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