if the domain of the function f:x= 2x^2 +1 is {-1,2,3} the range of the function is ___?
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Step-by-step explanation:
Correct option is
B
Doman=R,Range=(−∞,2]
Given f(x)=2−∣x−5∣
Domain of f(x) is defined for all real values of x.
Since, ∣x−5∣≥0⟹−∣x−5∣≤0
⟹2−∣x−5∣≤2⟹f(x)≤2
Hence, range of f(x) is (−∞,2].
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