Question

If the eight digit no. 2575d568 is divisible by 54 and 87, then the value of the digit 'd' is

Answer 1

Hey mate here is your answer-
54 = 2×3×3×3=2×3^3
87 = 3 ×29
The eight digit number 25,75d,568 must be divisible by 2 , 27 and 29.
So as to make it divisible by 27, it must be divisible by 3 at least.
From the divisibility rule for 3, the total of the digit must be divisible by 3.
Hence, 2 + 5 + 7 + 5 + d + 5 + 6 + 8 = 38 + d
d must be a single digit. So,
d = 1, 4 or 7.
But , if d = 1 and 4 then 25751568 and 25754568 are not divisible by 29.
Hence d = 7

Answer 2

Answer:

7

step by step explaination:

2575D568 should also be divisible by the sum of 54 that is 9.

the divisibility test of 9: the sum of the number must be divisible by 9.

so,

2+5+7+5+5+6+8=38

to make ot divisible by 9 D should be replaced by 7 .

now,

2+5+7+5+"7"+5+6+8=45 (which is devisible by 9, amd also 54)

"HOPE IT HELPS"