If the elastic limit of copper is 1.5xx10^(8) N//m^(2),determine the minimum diameter a copper wire can have under a load of 10.0 kgfind , if its elastic limit is not to be exceeded.
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diameter of copper wire would be 0.91 mm
given, elastic limit of copper, σ = 1.5 × 10^8 N/m²
load on copper wire, F = mg = 10kg × 9.8 m/s²
= 98 N
using formula, σ = F/(πd²/4)
⇒d = √{4F/πσ}
= √{4 × 98/3.14 × 1.5 × 10^8}
= √{392/4.71 × 10^-8 }
= √{83.2271} × 10-⁴
= 9.1 × 10-⁴ m ≈ 0.91 mm
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